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(F)=1000F^2
We move all terms to the left:
(F)-(1000F^2)=0
determiningTheFunctionDomain -1000F^2+F=0
a = -1000; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-1000)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-1000}=\frac{-2}{-2000} =1/1000 $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-1000}=\frac{0}{-2000} =0 $
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